A compound `C_(6)H_(14)O_(2)` has two tertiary alcoholic groups . The IUPAC name of this compound is

Options

A. 2,3-dimethyl -1, 2 - butanediol
B. 3,3-dimethyl - 1 , 2 - butanediol
C. 2,3-dimethyl-2 , 3-butanediol
D. 2-methyl-2 , 3- pentanediol .

Explanation

To determine the IUPAC name of the compound with the formula \( C_6H_{14}O_2 \) that contains two tertiary alcoholic groups, we can follow these steps:

### Step 1: Understand the Structure
We know that a tertiary alcohol is one where the carbon atom attached to the hydroxyl group (–OH) is also bonded to three other carbon atoms. Therefore, we are looking for a structure where both –OH groups are attached to tertiary carbons.

### Step 2: Determine the Carbon Skeleton
Given the molecular formula \( C_6H_{14}O_2 \), we can start by sketching a carbon chain that can accommodate two –OH groups. A suitable carbon skeleton for this compound could be a butane chain with two additional methyl groups.

### Step 3: Construct the Compound
We can construct the compound as follows:
- Start with a butane backbone (4 carbon atoms).
- Add two methyl groups on the second and third carbons.
- Attach the –OH groups to the second and third carbons.

The structure can be represented as:
```
CH3
|
CH3-C-CH-CH3
| |
OH OH
```

### Step 4: Number the Carbon Chain
Number the carbon chain from the end nearest to the first –OH group:
1. Carbon 1: CH3
2. Carbon 2: C(OH) with a methyl group
3. Carbon 3: C(OH) with a methyl group
4. Carbon 4: CH3

This gives us the numbering:
- C1: CH3
- C2: OH and CH3 (methyl)
- C3: OH and CH3 (methyl)
- C4: CH3

### Step 5: Write the IUPAC Name
The IUPAC name is derived from the structure:
- The longest carbon chain has 4 carbons (butane).
- There are two –OH groups, so we use "diol."
- The methyl groups at positions 2 and 3 give us "dimethyl."

Thus, the IUPAC name of the compound is **2,3-dimethyl-2,3-butanediol**.

### Final Answer
The IUPAC name of the compound \( C_6H_{14}O_2 \) with two tertiary alcoholic groups is **2,3-dimethyl-2,3-butanediol**.