The heat of combustion of ethane and benzene is `-1560` and `-3268" kJ mol"^(-1)` respectively. Which two has higher efficiency as fuel per gram and the amount of heat produced per gram?

Options

A. Benzene, `41.9" kJ g"^(-1)`
B. Ethane, `"52 kJ g"^(-1)`
C. Benzene, `"78 kJ g"^(-1)`
D. Ethane, `"30 kJ g"^(-1)`

Answer

B

Explanation

Heat produced by ethane `=(1560)/(30)="52 kJ g"^(-1)`
Heat produced by benzene `=(3268)/(78)="41.9 kJ g"^(-1)`