Home
Class 10
MATHS
In the adjoining figure AD and BE are th...

In the adjoining figure AD and BE are the perpendiculars on side BC and CA respectively of the `DeltaABC ` , Then , A, B, D, E are concyclic.

Text Solution

Verified by Experts

The correct Answer is:
1
since the angles `angleADB andangleAEB` on the same side of AB are equal for being right angles each.
Hence the four ponits A,B, D, E are concyclic , by theorem-36
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THEOREMS RELATED TO CYCLIC QUADRILATERAL

    CALCUTTA BOOK HOUSE|Exercise Fill in the blanks:|6 Videos

  • THEOREMS RELATED TO CYCLIC QUADRILATERAL

    CALCUTTA BOOK HOUSE|Exercise EXAMPLE (Short - answer type questions)|5 Videos

  • THEOREMS RELATED TO CYCLIC QUADRILATERAL

    CALCUTTA BOOK HOUSE|Exercise Long -answer type questions (L.A.)|12 Videos

  • THEOREMS RELATED TO CIRCLE

    CALCUTTA BOOK HOUSE|Exercise EXERCISE - 1 (Long - answer type question )|9 Videos

  • THEOREMS RELATED TO ANGLES IN A CIRCLE

    CALCUTTA BOOK HOUSE|Exercise EXERCISE 2.3 (Long Answer Type Questions)|14 Videos

Similar Questions

Explore conceptually related problems

In the adjoining figure AD and BE are perpendicular ot BC and AC respectively of the Delta ABC . The four points A,B,D,E are concylic.

If D,E and F are the middle points of the sides BC,CA and AB of the DeltaABC , then AD+BE+CF is

In the adjoining figure if DE||BC , then the value of x is

ABCD is parallelogram A circle passing through the points A and B intersect the sides AD and BC at the points E and F repectively . Prove that the four points E, F , C ,D are concyclic.

BE and CF are perpendicular on sides AC and AB of triangles ABC respectively . Prove that four points B , C ,E , F are concyclic. Also prove that the two angles of each of DeltaAEFandDeltaABC are equal.

In the figure D, E are points on the sides AB and AC respectively of DeltaABC such that ar(DeltaDBC) = ar(DeltaEBC) . Prove that DE || BC.

In the adjoining figure, If /_ADE=/_ACB , then DeltaADE~DeltaACB .

In the isosceles DeltaABC , AB = AC , O is any point on the side BC. OP and OQ are the perpendicular distance of the sides AB and AC from O respectively. BD is the perpendicular distance of AC from B. Show that OP + OQ = BD.

D, E and F are the mid-points of the sides AB, BC and CA of the DeltaABC . Prove that DeltaDEF=1/4DeltaABC .

In DeltaABC, D, E and F are the midpoints of sides AB, BC and CA respectively. Show that DeltaABC is divided into four congruent triangles, when the three midpoints are joined to each other. (ΔDEF is called medial triangle)

Home
Profile