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Tow beakers A and B of equal mass contai...

Tow beakers A and B of equal mass contain 5 moles of methane `(CH_(4))` and 5 moles of ammonia `(NH_(3))` respectively . Which beaker will be heavier ?

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The correct Answer is:
B
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The mass of 0.5 moles of methane is

The mass of 5 moles of ammonia (NH_(3)) is ………….

Knowledge Check

  • One mole of methane (CH_4) contains

    A
    `6.02xx10^(23)` atoms of Hydrogen
    B
    `1.204xx10^(24)` atoms of Carbon
    C
    `2.408xx10^(24)`atoms of Hydrogen
    D
    6 gm of Carbon
  • 5 moles of H_(2)SO_(4) contain

    A
    5 eq. of H
    B
    5 moles of S
    C
    20 eq. of O
    D
    10 eq. each of H, S and O
  • A buffer solution contains 1 mole of (NH_(4))_(2)SO_(4) and 1 mole of NH_(4)OH(K_(b)=10^(-5)) . The pH of solution will be:

    A
    `5`
    B
    `9`
    C
    `5.3`
    D
    `8.7`
  • Similar Questions

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    What is the number of molecules present in 1-5 mole of ammonia (NH_(3)) ?

    Two flasks A and B of equal volume are at temperature 100 K and 200 K containing H_(2) and CH_(4) , respectively. Which of the following is true about KE per mole ( KE= Kinetic energy).

    As Fig. shows, S_(1) and S_(2) , are spring balances. Block A is hanging from spring balance S_(1) and immersed in liquid L which is contained in beaker B . The mass of beaker B is 1 kg and mass of liquid L is 1.5 kg . Balances S_(1) and S_(2) reads 2.5 kg and 7.5 kg , respectively. What will be the readings of S_(1) and S_(2) when block A is pulled up out of the liquid. Find the reading of S_(1) and S_(2)?

    The number of moles of C and D produced on mixing 5 moles of A and 7 moles of B are respectively: (3A + 5B rArr 7C + 9D)

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