A particle of mass `0.5kg` travels in a straight line with velocity `v=ax^(3//2)` where `a=5m^(-1//2)s^-1`. What is the work done by the net force during its displacement from `x=0` to `x=2m`?

Explanation

`m=0.5kg`, `v=ax^(3//2)`, `a=5m^(-1//2)s^-1`, `W=?`
Initial velocity at `x=0`, `v_0=axx0=0`
Final velocity at `x=2`, `v_2=axx2^(3//2)=5xx2^(3//2)`
Work done=Increase in kinetic energy
`=1/2xx0.5[(5xx2^(3//2))-0^2]=50J`