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In a capillary tube of radius 'R' a stra...

In a capillary tube of radius 'R' a straight thin metal wire of radius 'r' (`Rgtr)` is inserted symmetrically and one of the combination is dipped vertically in water such that the lower end of the combination Is at same level . The rise of water in the capillary tube is [T=surface tensiono of water `rho` =density of water ,g =gravitational acceleration ]

A

`(T)/((R+r)rho g)`

B

`(R rho g)/(2T)`

C

`(2T)/((R-r)rho g)`

D

`((R-r )rho g)/(T)`

Text Solution

Verified by Experts

The correct Answer is:
C
According to question, rise of water in the capillary tube is given by
`h = (2T cos theta)/(rho g(R-r))`
[Symbols have their usual meanings]
In the given case,
`cos theta = 1` as `theta = 0^(@)`
So, `h = (2T)/(rho g(R-r))`
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