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In 1 g of a solid, there are 5xx10^(21) ...

In `1 g` of a solid, there are `5xx10^(21)` atoms. If one electrons is removed from each of 0.01% atoms of the solid, find the charge gained by the solid (given that electronic charge is `1.6xx10^(19)C` ).

A

`+0.08C`

B

`+0.8C`

C

`-0.08C`

D

`-0.8C`

Text Solution

Verified by Experts

The correct Answer is:
A
Number of atom in 1 g of a solid
`n=(0.01)/(100)xx5xx10^(21)=5xx10^(17)`
`q=-n =-5xx10^(-17)(-1.6xx10^(-19))=+0.08C`
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Knowledge Check

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