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In 1 g of a solid, there are 5xx10^(21) ...

In `1 g` of a solid, there are `5xx10^(21)` atoms. If one electrons is removed from each of 0.01% atoms of the solid, find the charge gained by the solid (given that electronic charge is `1.6xx10^(19)C` ).

A

`+0.08C`

B

`+0.8C`

C

`-0.08C`

D

`-0.8C`

Text Solution

Verified by Experts

The correct Answer is:
A

Number of atom in 1 g of a solid
`n=(0.01)/(100)xx5xx10^(21)=5xx10^(17)`
`q=-n =-5xx10^(-17)(-1.6xx10^(-19))=+0.08C`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-ELECTROSTATICS-PRACTICE EXERCISE (Exercise 2 (MISCELLANEOUS PROBLEMS))
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  9. A circuit is shown in figure for which C(1)=(3pm 0.011)muF, C(2)=(5pm ...

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  10. Charges +2Q and -Q are placed as shown in figure. The point at which e...

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  14. If the equivalent capacitance between points P and Q of the combinatio...

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  15. An electric field is given by E=(y hati+x hatj)NC^(-1). The work done ...

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  16. A circular ring carries a uniformly distributed positive charge and li...

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  17. A conducting sphere of radius 5 cm has an unknown charge. The electric...

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  18. Charge Q is given by the displacement r=a hati+bhat j in an electrif f...

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  19. If the electric flux entering and leaving an enclosed surface respecti...

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