In a region `10^(19) prop`-particles and `10^(19)` protons move to the left, while `10^(19)` electrons moves to the right per second. The current is

Options

A. 3.2 A towards left
B. 3.2 A towards right
C. 6.4 A towards left
D. 6.4 A towards right

Explanation

To find the total current in the given scenario, we will consider the contributions from the alpha particles, protons, and electrons separately.

### Step-by-Step Solution:

1. **Identify the Charges of the Particles:**
- Alpha particles have a charge of \( +2e \) (where \( e = 1.6 \times 10^{-19} \) C).
- Protons have a charge of \( +1e \).
- Electrons have a charge of \( -1e \).

2. **Determine the Number of Each Type of Particle:**
- Number of alpha particles = \( 10^{19} \)
- Number of protons = \( 10^{19} \)
- Number of electrons = \( 10^{19} \)

3. **Calculate the Current Due to Each Type of Particle:**
- **Current due to alpha particles (\( I_1 \)):**
\[ I_1 = \text{Number of alpha particles} \times \text{Charge of one alpha particle} = 10^{19} \times 2e = 10^{19} \times 2 \times (1.6 \times 10^{-19}) = 3.2 \, \text{A} \]
- **Current due to protons (\( I_2 \)):**
\[ I_2 = \text{Number of protons} \times \text{Charge of one proton} = 10^{19} \times e = 10^{19} \times (1.6 \times 10^{-19}) = 1.6 \, \text{A} \]
- **Current due to electrons (\( I_3 \)):**
\[ I_3 = \text{Number of electrons} \times \text{Charge of one electron} = 10^{19} \times (-e) = 10^{19} \times (-1.6 \times 10^{-19}) = -1.6 \, \text{A} \]

4. **Determine the Direction of Current:**
- The current due to alpha particles and protons is towards the left (positive direction).
- The current due to electrons is towards the right (negative direction).

5. **Calculate the Total Current:**
\[ I_{\text{total}} = I_1 + I_2 + I_3 = 3.2 \, \text{A} + 1.6 \, \text{A} - 1.6 \, \text{A} = 3.2 \, \text{A} \]
Since both alpha particles and protons contribute to the current towards the left, the total current is \( 3.2 \, \text{A} \) towards the left.

### Final Answer:
The total current is \( 3.2 \, \text{A} \) towards the left.