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Which of the following statement (s) is ...

Which of the following statement (s) is /are correct?
(I) In acidic solution dichromate ions are converted to chromate ions .
(II) An acidified solution of `K_(2)Cr_(2)O_(7)` liberates iodine from iodides.
(III) Potassium dichromate is used as a titrant for `Fe^(2+)` ions.
(IV) Ammonium dichromate on heating undergo exothermic decomposition to give `Cr_(2)O_(3)`.
Choose the correct option .

A

I,II and III

B

II,III, and IV

C

I,II,III and IV

D

II and III

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the statements are correct, let's analyze each statement one by one. ### Step 1: Analyze Statement I **Statement I**: In acidic solution, dichromate ions are converted to chromate ions. - **Analysis**: This statement is incorrect. In acidic solutions, dichromate ions \((Cr_2O_7^{2-})\) are not converted to chromate ions \((CrO_4^{2-})\). Instead, they remain as dichromate ions. The conversion from dichromate to chromate occurs in alkaline solutions. ### Step 2: Analyze Statement II **Statement II**: An acidified solution of \(K_2Cr_2O_7\) liberates iodine from iodides. - **Analysis**: This statement is correct. In an acidified solution, potassium dichromate (\(K_2Cr_2O_7\)) can oxidize iodide ions \((I^-)\) to iodine \((I_2)\). The reaction can be represented as: \[ K_2Cr_2O_7 + 14H^+ + 6I^- \rightarrow 2Cr^{3+} + 7H_2O + 3I_2 \] Thus, iodine is liberated from iodides. ### Step 3: Analyze Statement III **Statement III**: Potassium dichromate is used as a titrant for \(Fe^{2+}\) ions. - **Analysis**: This statement is correct. Potassium dichromate is commonly used as a titrant in redox titrations involving \(Fe^{2+}\) ions. The half-reaction for the dichromate reduction and the oxidation of \(Fe^{2+}\) to \(Fe^{3+}\) confirms this: \[ Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O \] \[ Fe^{2+} \rightarrow Fe^{3+} + e^- \] By balancing these reactions, we can see that potassium dichromate effectively titrates \(Fe^{2+}\). ### Step 4: Analyze Statement IV **Statement IV**: Ammonium dichromate on heating undergoes exothermic decomposition to give \(Cr_2O_3\). - **Analysis**: This statement is correct. Ammonium dichromate \((NH_4)_2Cr_2O_7\) decomposes upon heating to produce chromium(III) oxide \((Cr_2O_3)\), nitrogen gas \((N_2)\), and water. The reaction is exothermic and can be represented as: \[ (NH_4)_2Cr_2O_7 \rightarrow Cr_2O_3 + N_2 + 4H_2O \] The reaction is characterized by the release of heat and an orange spark. ### Conclusion Based on the analysis: - **Statement I**: Incorrect - **Statement II**: Correct - **Statement III**: Correct - **Statement IV**: Correct Thus, the correct statements are II, III, and IV. ### Final Answer The correct option is **II, III, and IV**. ---

To determine which of the statements are correct, let's analyze each statement one by one. ### Step 1: Analyze Statement I **Statement I**: In acidic solution, dichromate ions are converted to chromate ions. - **Analysis**: This statement is incorrect. In acidic solutions, dichromate ions \((Cr_2O_7^{2-})\) are not converted to chromate ions \((CrO_4^{2-})\). Instead, they remain as dichromate ions. The conversion from dichromate to chromate occurs in alkaline solutions. ### Step 2: Analyze Statement II ...
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Knowledge Check

  • Which of the following statement (s) is/are correct? I. In acidic solution dichromate ions are converted to chromate ions. II. An acidified solution of K_2Cr_2O_7 liberates iodine from iodides. III. Ammonium dichromate on heating undergo exothermic decomposition to give Cr_2O_3 . Choose the correct option.

    A
    Only II
    B
    II and III
    C
    Only II
    D
    All of these
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    A
    `SO_(2)` is reduced
    B
    Green `Cr_(2)(SO_(4))_(3)` is formed
    C
    The solution turns blue
    D
    The solution is decolourised
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    A
    `CrSO_(4)`
    B
    `Cr_(2)(SO_(4))_(3)`
    C
    `K_(2)SO_(4)`
    D
    `S`
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