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A particle starts moving rectilinearly a...

A particle starts moving rectilinearly at time t = 0 such that its velocity v changes with time t according to the equation `v = t^2-t`, where t is in seconds and v is in `m s^(-1)`. The time interval for which the particle retrads (i.e., magnitude of velocity decreases)is

A

`t lt 1//2`

B

`1//2 ltt lt1`

C

`tgt1`

D

`tlt1//2 and tgt1`

Text Solution

Verified by Experts

The correct Answer is:
B
b. ` v= t^2-t rArr a = 9dv)/(dt) = 2t - 1 `
For retardation, `avlt0`
`rArr (t^2-t)(2t-1)lt0`
` rArr t(t-1)(2t-1)lt0`
This is possible for `1/2lttlt1`.
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