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Explain why cu^(+) ion is not stable in ...

Explain why `cu^(+)` ion is not stable in aqueous solutions?

Text Solution

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In aqueous solution, `Cu^(+)` ( aq) undergoes disproportionation reaction as follows.
`2Cu^(+)(aq) rarr Cu^(2+) (aq)+Cu(s)`
The higher stability of `Cu^(2+)` (aq) in aqueous solution is due to higher negative enthalpy of hydration `Delta_(hyd)H^(@)` than that of `Cu^(+)`(aq). It compensates the second IE of Cu involved in the formation of `Cu^(2+)` ion. Hence, `Cu^(+)` ion changes to more stable `Cu^(2+)` ion in aqueous medium.
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Knowledge Check

  • Cu^(+) ion is not stable in aqueous solution because

    A
    `Cu_((aq))^(+2)` is more stable than `Cu_((aq))^(+)`
    B
    `Cur_((aq))^(+2)` can form interstitial compounds in aqueous solution
    C
    The equilibrium constant for `Cu_((aq))^(+) hArr Cu_((aq))^(+2) + Cu` is very high
    D
    The equilibrium constant for `Cu_((aq))^(+2) hArr Cu_((aq))^(+2) = Cu` is very low

  • Cu^+ ion is not stable in aqueous solution because of diproportionation reaction . E^(@) value for the disproportionation of Cu^(+) is : (E_(cu^(2+)// cu^+)^(@) = + 0.15 V , E_(cu^(+) // cu)^(@)= + 0.34 V )

    A
    `-0.19 V `
    B
    `-0.38 V `
    C
    `+ 0.19 V `
    D
    `+ 0.38 V `

  • Which one of the following ions is the most stable in aqueous solution (At.No. Ti = 22, V = 23, Cr = 24, Mn = 25)

    A
    `V^(3+)`
    B
    `Ti^(3+)`
    C
    `Mn^(3+)`
    D
    `Cr^(3+)`

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