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Explain why phenol with bromine water fo...

Explain why phenol with bromine water forms 2,4,6-tribromophenol while on reaction with bromine in `CS_(2)` at low temperature forms para-bromophenol as the major product .

Text Solution

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a) Phenol undergoes Bromination in presence of `CS_(2)` to form p-bromophenol as major product

b) Phenol undergoes bromination in aqueous medium form 2,4,6-tribrome phenol (white ppt).

Explain : In bromination of phenol, the polarisation of `Br_(2)` molecule takes place even in the absence of Lewis acid. This is due to be highly activating effect of -OH group attached to teh benzene ring.
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Knowledge Check

  • The products formed in the reaction of phenol with Br, dissolved in CS_(2) at 0^(@)C are

    A
    o-bromo, m-bromo and p-bromophenols
    B
    o-bromo and p-bromophenols
    C
    2,4,6-tribromo and 2,3,6-tribromophenols
    D
    2,4-dibromo and 2,6-dibromophenols

  • Br_(2) dissolved in CS_(2) reacts with phenol at 273K to give …............ as the major product

    A
    o - Bromophenol
    B
    m - Bromophenol
    C
    P - Bromophenol
    D
    2, 4, 6 - Tribromophenol

  • The product formed in the oxidation of glucose with bromine water is

    A
    Glucaric acid
    B
    Gluconic acid
    C
    Glucuronic acid
    D
    Sorbitol

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    Aceton forms a trimer on heating with conc. H_2 SO_4 . The product is

    Regarding phenol the correct statements are A) It reacts with B_2//CS_2 to give a mixture of o-bromophenol and p-bromophenol B) In Riemer-Tiemann reaction with CHCl_3 a substituted benzalchloride intermediate is formed C) In Kolbe's reaction gives salicylic acid D) On oxidation with it gives a conjugated diketone

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