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Determine the voltage drop across the re...

Determine the voltage drop across the resistor `R_1` in the circuit given below with `E = 65V, R_1 = 50 OmegaR_2 = 100 Omega, R_3 = 100 Omega, and R_4 300 Omega.

Text Solution

Verified by Experts

`R_3 and R_4` are in series. The combined resistance is `400 Omega.`
Now `R_2 (-100Omega)and 400Omega` resistance are in parallel. The
combined resistance is `(100xx400)//500 = 80Omega.`
Total resistance is `R = 80 +50 = 130 Omega`
`I = 65//130 = 1//2A.`
So, `V = IR_1 = 1.//2 xx50 = 25V`
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Knowledge Check

  • The potential difference in volt across the resistance R_(3) in the circuit shown in figure, is (R_(1)=15Omega,R_(2)=15Omega, R_(3)=30Omega, R_(4)=35Omega)

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    `1.6 A`
    B
    `1.8 A`
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  • In the circuit given in fig. (V_C)=50 V and R=50 Omega . The values of C and (V_R) are

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