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In the circuit shown in fig. the cell is...

In the circuit shown in fig. the cell is ideal with emf 15V. Each resistance is of `3Omega.` The potential difference across the capacitoro in steady state is

A

0

B

9 V

C

12 V

D

15 V

Text Solution

Verified by Experts

The correct Answer is:
C
As the capacitors are identical, each of them finally have
chargel Q//2.
Initial energy of the system in `E_(1) = (Q^(2))/(2C)`
Final energy of the system is `E_(f)=2[((Q//2)^(2))/(2C)]=(Q^(2))/(4C)`
Heat produced = loss in energy `=E_(i) - E_(f) = (Q^(2))/(4C)`
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Knowledge Check

  • In the circuit shown, the cell is ideal , with emf= 15 V . Ecah resistance is of 3 Omega. the potential difference across the capacitor is

    A
    zero
    B
    `9V`
    C
    `12 V`
    D
    `15 V`

  • In the circuit shown the cell is idea with end =15V each resistance is of 3Omega The potential difference the capacitor is

    A
    zero
    B
    `9V`
    C
    `12V`
    D
    `15V`

  • In the circuit shown in fig. the cell has emf 10V and internal resistance 1 Omega

    A
    The current through the `3Omega` resistor is 1A.
    B
    The currents through the `3 Omega` resistor is 0.5 A.
    C
    The currents through the `4 Omega` resistor is 0.5 A
    D
    The current through the `4Omega` resistor is 0.25 A.

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