Two liquid A and B are at `32^@C` and `24^@C`. When mixed in equal masses the temperature of the mixture is found to be `28^@C`. Their specific heats are in the ratio of

Options

A. `3:2`
B. `2:3`
C. `1:1`
D. `4:3`

Answer

C

Explanation

Heat lost by `A=` heat gained by B
`impliesm_Axxc_Axx(T_A-T)=m_Bxxc_Bxx(T-T_B)`
Since `m_A=m_B` and temperature of the mixture `(T)=28^@C`
`:. C_Axx(32-28)=c_Bxx(28-24)`
`implies(c_A)/(c_B)=1:1`