A glass container encloses a gas a pressure of `8 xx 10^(5)` pa and 300 K temperature. The container walls can bear a maximum pressure of `10^(6)` Pa. If the temperature of container is gradually increased, find the temperature at which the container will break.

Explanation

From gas law, we have for a constant volume container
`(P_(1))/(T_(1)) = (P_(2))/(T_(2))`
or `T_(2) = ((P_(2))/(P_(1))) = T_(1)`
Given that `P_(1) = 8 xx 10^(5) Pa, T_(1) = 300 K, P_(2) = 10^(6) Pa`,
then we have
`T_(2) = (10^(6))/(8 xx 10^(5)) xx 300 = 375 K`