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Consider the ioselectronic series , K^(o...

Consider the ioselectronic series , `K^(o+), S^(2-), Cl^(ɵ), Ca^(2+)`, the radii of the ions decrease as

A

`Ca^(2+) gt K^(o+) gt Cl^(ɵ) gt S^(2-)`

B

`Cl^(ɵ) gt S^(2-) gt K^(o+) gt Ca^(2+)`

C

`S^(2-) gt Cl^(ɵ) gt K^(o+) gt Ca^(2+)`

D

`K^(o+) gt Ca^(2+) gt S^(2-) gt Cl^(ɵ)`

Text Solution

Verified by Experts

The correct Answer is:
C
Among the isoelectronic species, the ionic radii decreases as
More negative charge `gt` Less negative charge `gt` Neutral atom `gt` Less positive charge `gt` More positive charge.
Hence, the answer is
`ul(bar(S^(2-) gt Cl^(ɵ) gt K^(o+) gt Ca^(2+)))`
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