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Ionisation of energy F^(ɵ) is 320 kJ mol...

Ionisation of energy `F^(ɵ)` is `320 kJ mol^(-1)`. The electronic gain enthalpy of fluorine would be

A

`-320 kJ mol^(-1)`

B

`-160 kJ mol^(-1)`

C

`+320 kJ mol^(-1)`

D

`+160 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`IE` and `EA` of an element are equal in magnitude but opposite in sign.
`:. IE = -EA`
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