Write the Lewis structure for `CN^(Θ)` ion .

Explanation

Using the second method:
Step-1:V(Total no of valence `e^(-,)s)`
`=1x6("for C")+5xx6("for O")+2` (for two -ve charge)
`=38e^(-,)s`
Step-2: O (Total no. of `e^(-,)s` for octet)
`=1xx8("for "S)+5xx8("for "O)`
`=48e^(-,)s`
Step-3: S (shared `e^(-,)s`)
`=(O-V)=48-38=10e^(-,)s`
Step-4: Skeletal structure with 10 shared

step-5: U (unshared `e^(-,)s`) `=(V-S)`
`=38-10=28e^(-,)s`
step-6: Add 28 unshared `e^(-,)`'s to complete the lewis structure .

Note: (x) represents one unshared electrone So, the number of unshared `e^(-,)s=28`