`NO` is paramagnetic, while `NO^(oplus)` is diamagnetic.

Explanation

`NO` is paramagnetic, while `NO^(oplus)` is diamagnetic. This can be explained as follows :
`sigma 1s^2 lt sigma^** 1s^2 lt sigma 2s^2 lt sigma^** 2s^2 lt sigma 2o_z^2 lt pi 2 p_x^2 = pi 2 p_y^2 lt pi^** 2 p_x^1 = pi^** 2p_y^0 lt sigma^** 2 p_z^0`
Due to presence of unpaired electron in `pi^** 2p_x` orbital, `NO` is paramagnetic.
Electronic configuration on `NO^(oplus) (7 + 8 - 1 = 14 "electrons")`
`sigma 1s^2 lt sigma^** 1s^2 lt sigma 2s^2 lt sigma^** 2s^2 lt sigma 2o_z^2 lt pi 2 p_x^2 = pi 2 p_y^2 lt pi^** 2 p_x^0 = pi^** 2p_y^0 lt sigma^** 2 p_z^0`
Since all the electrons in `NO` molecule are paired up, `NO^(oplus)` is diamagnetic in nature.