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Sodium iodate is treated with calculated...

Sodium iodate is treated with calculated amount of sodium bisulphite to prepare one mole of iodine. How many moles of sodium disulphite are required to prepare one mole of iodine form sodium iodate ?

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The correct Answer is:
5
`2NaIO_(3)+underset(5mol)5NaHSO_(3)rarr 3NaHSO_(4) +2Na_(2)SO_(4)+H_(2)O+I_(2) underset(1mol)`
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