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Noble gases have compleately filled vala...

Noble gases have compleately filled valance shall i.e. `m^(2)sp^(2)` exceps He (i.e) .Noble gases are monoomic under normal conductions .Law bolding point of the ligher noble gases are due to weak van dor wads forces between the atoms and abance of any interature imaractions `Xe` reacts with `F_(2)` so give a sourceof fouoxide mently `XeF_(2),XeF_(4),XeF_(4),XeF_(3)` on complete hydrolyes gives `XeFe_(3)`,
Structure of `XeF_(4)` is

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The correct Answer is:
b
`Xe` in `XeF_(4)` is `sp^(3)d^(2)` hybridised with `2lps`
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Noble gases have compleately filled valance shall i.e. m^(2)sp^(2) exceps He (i.e) .Noble gases are monoomic under normal conductions .Law bolding point of the ligher noble gases are due to weak van dor wads forces between the atoms and abance of any interature imaractions Xe reacts with F_(2) so give a sourceof fouoxide mently XeF_(2),XeF_(4),XeF_(4),XeF_(3) on complete hydrolyes gives XeFe_(3) , Oxidetion state of Xe in XeF_(2) is

Noble gases have compleately filled valance shall i.e. m^(2)sp^(2) exceps He (i.e) .Noble gases are monoomic under normal conductions .Law bolding point of the ligher noble gases are due to weak van dor wads forces between the atoms and abance of any interature imaractions Xe reacts with F_(2) so give a sourceof fouoxide mently XeF_(2),XeF_(4),XeF_(4),XeF_(3) on complete hydrolyes gives XeFe_(3) , Argon is used in are welting due to its

Noble gases have compleately filled valance shall i.e. `m^(2)sp^(2)` exceps He (i.e) .Noble gases are monoomic under normal conductions .Law bolding point of the ligher noble gases are due to weak van dor wads forces between the atoms and abance of any interature imaractions `Xe` reacts with `F_(2)` so give a sourceof fouoxide mently `XeF_(2),XeF_(4),XeF_(4),XeF_(3)` on complete hydrolyes gives `XeFe_(3)`,
`XeF_(4)` and `XeF_(4)` are expected to be

Give the molecular structures of :
`XeF_(2),XeF_(4),XeF_(6)`
`XeOF_(4) " and " XeO_(3)`

In `XeF_(2),XeF_(4) and XeF_(6)`, the number of lonepairson Xe are respectively

The structure of the noble gas compound XeF_(4) is :

The noble gases have closed -shell electronic configuration and are monoatomic gases under normal conditions. The low bp of the ligher noble bp of the lighter noble gases are due to weak dispersion force between the atoms and the absence of other interatomic interactions. The direct reaction of xenon with fluorine leads to a series of compounds with oxidation numbers +2,+4 and +6 . XeF_(4) reacts violently with water to give XeO_(3) . the compound of xenone exhibit rich stereochemistry and their geometries can be deduced considering the total number of electron pairs in the valence shell. XeF_(4) and XeF_(6) are expected to be

The structure of the noble gas compound `XeF_(4)` is :

क्रमश: `XeF_(2), XeF_(4)` , एवं ` XeF_(6)` में Xe की संकरण अवस्था है -

Xe reacts with `F_(2)` at different ratio to give different types of xenon fluorides.
`Xe+ Fe rarr XeF_(2)`
(2:1)
`Xe +F_(2) rarr XeF_(4)`
(1:5)
`Xe + F_(2) rarr XeF_(6)`
(1: 20)
The sbape and hybridisation of `XeF_(4 )` is

Noble gases have compleately filled valance shall i.e. ns^(2)np^(6) exceps He (i.e) .Noble gases are monoomic under normal conductions .Law bolding point of the ligher noble gases are due to weak van dor wads forces between the atoms and abance of any interature imaractions Xe reacts with F_(2) so give a sourceof fouoxide mently XeF_(2),XeF_(4),XeF_(4),XeF_(3) on complete hydrolyes gives XeFe_(3) , Structure of XeF_(4) is

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