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What is the oxidation number of Xe in Xe...

What is the oxidation number of `Xe` in `XeOF_(2)`?

Text Solution

Verified by Experts

The correct Answer is:
4
Let oxidation number of `Xe` in `XeOF_(2)` is 'x'
`x + (-2) xx 1 (-1) xx 2 = 0`
`x = +4`
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Knowledge Check

  • The oxidation number of xenon in XeOF_(2) is

    A
    Zero
    B
    `2`
    C
    `4`
    D
    `3`

  • What is the oxidation number of Mo in MoO_(2)Cl_(2) ?

    A
    0
    B
    `+3`
    C
    `+5`
    D
    `+6`

  • The oxidation number of xenon in XeOF_4 is

    A
    Zero
    B
    2
    C
    4
    D
    3

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    Oxidation number of Xe in XeF_(5)^(-) is :

    A compound of Xe and F is found to have 53.5% Xe. What is the oxidation number of Xe in this comound?

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