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Acidified K2Cr2O7 solution turns green w...

Acidified `K_2Cr_2O_7` solution turns green when sodium sulphite is added to it. Explain.

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`Cr_2O_7^(2-)+8H^(ɵ)+3SO_3^(2-)tounderset(green)(2Cr^(3+)+3SO_4^(2-)+4H_2O`
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Write the equations . (i) Acidified solution of K_(2)Cr_(2)O_(7) turns green when sodium sulphite is added to it. (ii) Potassium ferricyanide is added to ferrous sulphate . (iii) Silver chloride is treated with aqueous sodium cyanide . (iv) Zinc is exposed to moist air .

Acidified K_2 Cr_2 O_7 turns green by

Knowledge Check

  • Acidified K_(2)Cr_(2)O_(7) solution turns green when NasO_(3) is added to it. This is due to the formation of :

    A
    `Cr_(2)(SO_(4))_(3)`
    B
    `CrO_(4)^(2-)`
    C
    `Cr_(2)(SO_3)_3`
    D
    `CrSO_(4)`

  • Acidified K_(2)Cr_(2)O_(7) , solution turns green when Na_(2)SO_(3) is added to it. Thus is due to the formation of

    A
    `Cr_(2)(SO_(4))_(3)`
    B
    `CrO_(4)^(2-)`
    C
    `Cr_(2)(SO_(3))_(3)`
    D
    `CrSO_(4)`

  • Acidified K_(2)Cr_(2)O_(7) solution turns green when Na_(2)SO_(3) is added to it. This is due to the formation of

    A
    `CrO_(4)^(2-)`
    B
    `Cr_(2)(SO_(3))_(3)`
    C
    `CrSO_(4)`
    D
    `Cr_(2)(SO_(4))_(3)`

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    $ Acidified K_(2)Cr_(2)O_(7) is turned green when SO_(2) is passed thorugh it. ! In this reaction SO_(2) acts as a reducing agent.

    Acidified Acidified K_(2)Cr_(2)O_(7) solution turns green when Na_(2)SO_(3) is added it this is due to the formation of

    Acidified Acidified K_(2)Cr_(2)O_(7) solution turns green when Na_(2)SO_(3) is added it this is due to the formation of

    Statement-1 :Acidified K_(2)Cr_(2)O_(7) solution becomes green when SO_(2) gas is passed through it. Statement-2 :This is an redox reaction.

    If(X) turns acidified K_(2)Cr_(2)O_(7) solution green , then then X may be

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