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How many geometrical isomers are there f...

How many geometrical isomers are there fore
(a)`[Co(NH_(3))_(2)CI_(4)]^(Θ)`
(b) `[AuCI_(2)Br_(2)]^(Θ)` (square planar) (c ) `[CuCI_(2)Br_(2)]^(2-)` (tetrahedral) .

Text Solution

Verified by Experts

Since `[Co(NH_(3))_(2)CI_(4)]^(Θ)` is `a [Ma_(2)b_(4)]` type octahedral complex ion it has two geometrical isomers which are cis and trans as shown below

(b) Since `[AuCI_(2)Br_(2)]^(Θ)` ion is `[Ma_(2)b_(2)]` type square planar complex ion it has two geometrical isomers viz cis and trans isomers
(c ) `[CuCI_(2)Br_(2)]^(2-)` is tetrahedral and hence has no geometrical isomer .
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How many geometrical isomers are there for (a) [CO(NH_(3))_(2)Cl_(4)] , octahedral (b) [AuCl_(2)Br_(2)] square planar (c) (CoCl_(2)Br_(2)] tetrahedral

How many geometrical isomers are there for (a) [CO(NH_(3))_(2)Cl_(4)] , octahedral (b) [AuCl_(2)Br_(2)] square planar (c) (CoCl_(2)Br_(2)] tetrahedral

Knowledge Check

  • How many geometrical isomers are there for [Co(NH_(3))_(2)Cl_(4)]^(-), and [AuCl_(2)Br_(2)]^(-) ?

    A
    Two cis and trans, no geometrical isomers
    B
    Two cis and trans, two cis and trans
    C
    No geometrical isomers, two cis and trans
    D
    No geometrical isomers, no geometrical isomer
  • The number of geometrical isomers for [Pt(NH_(3))_(2)CI_(2)] is

    A
    3
    B
    4
    C
    1
    D
    2
  • How many geometrical isomers are possible for [Pd^(2+)(NH_(2)-CH(CH_(3))-CO_(2)^(-))_(2)]^(0)

    A
    `2`
    B
    `3`
    C
    `4`
    D
    `6`
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