Home
Class 12
CHEMISTRY
The 0.0001 molal solution of a complex A...

The `0.0001` molal solution of a complex `AB_(10)` has the freezing point of `-0.0015^(@)C` in water. Assuming `100%` dissociation of the complex, find the proper representation of the complex `[K_(f)(H_(2)O=1.86Km^(-1))]`
(a) `[AB_(8)]`
(b) `[AB_(3)]B_(7)`
(c )` [AB_(7)]B_(3)`
(d) `[AB_(5)]B_(5)` .

Doubtnut Promotions Banner Mobile Dark

Text Solution

Verified by Experts

The correct Answer is:
b

At `100%` dissociation van t Hoff vactor if `I = n` (no of ions from the complex
Now `deltaT_(f)|=iK_(f)m`
`implies i = n= (|DeltaT_(f)|)/(K_(f)m) = (0.0015)/(1.86 xx 0.0001) = 8`
implies Thus there should be 8 ions in solution
implies The compound should be `[AB_(3)]B_(7))` .
|

Topper's Solved these Questions

  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Exercises Linked Comprehension|39 Videos
  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Exercises Multiple Correct(Naming And Terminology)|9 Videos
  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Ex 7.2 Subjective|4 Videos
  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY|Exercise Archives Subjective|23 Videos
  • D AND F BLOCK ELEMENTS

    CENGAGE CHEMISTRY|Exercise Archives Subjective|29 Videos

Similar Questions

Explore conceptually related problems

If two gases AB_(2) and B_(2)C are mixed, following equilibria are readily established: AB_(2)(g)+B_(2)C(g)rarr AB_(3)(g)+BC(g) , BC(g)+B_(2)C(g) rarr B_(3)C_(2)(g) If the reaction is started only with AB_(2) with B_(2)C , then which of the following us necessarily true at equilibrium?

For a hypothetical reaction of kind.
`AB_(2)(g)+1/2 B_(2)(g) hArr AB_(3)(g), DeltaH=-x kJ`
More `AB_(3)` could be produceed at equilibrium by

`AB_(3)(g)` is dissociation as `AB_(2)(g) hArr AB_(2)(g)+(1)/(2)B_(2)(g)`,
When the initial pressure of `AB_(2)` is 800 torr and the total pressure developed at equilibrium is 900 torr. What fraction of `AB_(3)(g)` is dissociated ?

Which has maximum solubility `AB,AB_(2),AB_(3)` and `AB_(4)` if `K_(SP)` for all the salts are `10^(-10) :`

AB_(3)(g) is dissociates as AB_(3)(g)hArrAB_(@)(g)+(1)/(2)B_(@)(g) When the initial pressure of AB_(3) is800 torr and the pressure developed at equilibrium is 900 torr , what fraction of AB_(3)(g) is dissociated?

A and B are two element which form `AB_(2) and A_(2)B_(3)`. If 0.18 mol of `AB_(2)` weighs 10.6g and 0.18 mol of `A_(2)B_(3)` weighs 17.8g then -

The reaction -rate of the reaction AB_(3)rarr(1)/(2)A_(2)+(3)/(2)B2 can be expressed by any one of the following equations : (-d[AB_(3)])/(dt)=k_(1)[AB_(3)], (d[A_(2)])/(dt)=k_(2)[AB_(3)] " or, " (d[B_(2)])/(dt)=k_(3)[AB_(3)] The ratio between k_(1) , k_(2)and k_(3) is -

AB_(2) dissociates as AB_(2(g)) Leftrightarrow AB_((g))+B_((g)) . Whwn the initial pressure of AB_(2) is 600mm of Hg, the total equilibrium pressure is 800mm of Hg. Calculate K_(p) for the reaction, assuming that the volume of the system remains unchanged

In the decomposition reaction `AB_(5)(g)hArrAB_(3)(g)+B_(2)(g)`, at equilibrium in a 10 litre closed vessel at `227^(@)C`, 2 moles of `AB_(3)`, 5 moles of `B_(2)` and 4 moles of `AB_(5)`, are present. The equilibrium contstant `K_(c)` for the formation of `AB_(5)(g)` is

If two gases `AB_(2)` and `B_(2)C` are mixed, following equilibria are readily established:
`AB_(2)(g)+B_(2)C(g)rarr AB_(3)(g)+BC(g)`,
`BC(g)+B_(2)C(g) rarr B_(3)C_(2)(g)`
If the reaction started only with `AB_(2)` with `B_(2)C`, then which of the following is necessarily true at equilibrium?

For the reaction `AB_(2(g)) hArr AB_((g)) + B_((g))` if `alpha` is negligiable w.rt 1 then degree of dissociation `(alpha)` of `AB_(2)` is proportional to

AB_(3)(g) is dissociates as AB_(3)(g)hArrAB_(2)(g)+(1)/(2)B_(2)(g) When the initial pressure of AB_(3) is800 torr and the pressure developed at equilibrium is 900 torr , what fraction of AB_(3)(g) is dissociated?

AB_(2(g)) dissociates as AB_(2(g)) harr AB_(2(g))+B_((g)) . The initial pressure of AB_2 is 600 mm Hg and equilibrium pressure of the mixture of gases is 800 mm Hg. Then

दो किरणें `L_(1)` तथा `L_(2)` बिन्दु 'A' से `30^(@)` कोण पर खींची गई है बिन्दु B, `L_(1)` पर A 1 ईकाई दूरी पर है। B से `L_(2)` पर एक अभिलम्ब `B B_(1)` खींचा गया है `B_(1)` से AB पर any अभिलम्ब `B_(1)B_(2)` खींचा गया है `B_(2)` से `AB_(1)` पर अभिलम्ब `B_(2)B_(3)` खींचा गया है यह क्रम इसी प्रकार चलता रहता है।
`AB,AB_(1),AB_(2),AB_(3),`. . . . . . .. है -