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When Zn reacts with cone ,HNO(3),then Zn...

When Zn reacts with cone ,`HNO_(3),then Zn(NO_(3)) and NO_(2)` are formed , the reaction (s) involved in this process is/are

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Explore conceptually related problems

Quantity of 1.5g brass containing Cu,Zn reacts with `3M,HNO_(3)` solution, the following reactions takes place
`Cu +HNO_(3) rarr Cu^(2+) +NO_(2) +H_(2)O`
`Zn +H^(+) +NO_(3)^(-) rarr NH_(4)^(+) +ZN^(2+) +H_(2)O` (un balanced)
The liberated `NO_(2)(g)` is found to occupy 1.04 litre at `25^(@)C` and 1 atm pressure. Now answer the following question
Weight of `NH_(4)NO_(3)` formed in the reaction is

Balance the following equation by oxidation number method Zn+HNO_(3) to Zn(NO_(3))_(2)+NH_(4)NO_(3)+H_(2)

For the redox reaction Zn+NO_(3)^(-)rarr Zn^(2+)+NH_(4)^(-) is basic medium, coefficients of Zn, NO_(3)^(-) and OH^(-) in the balanced equation respectively are :

निम्नलिखित समीकरण को ऑक्सीकरण संख्या विधि के द्वारा संतुलित कीजिए-
`Zn+HNO_(3) to Zn(NO_(3))_(2)+NH_(4)NO_(3)+H_(2)O`

For the redox reaction, `Zn+NO_(3)^(-) to Zn^(2+)+NH_(4)^(+)`. In basic medium, coefficients of `Zn, NO_(3)^(-) and OH^(-)` in the balanced reaction respectively, are

For the redox reaction, Zn + NO_(3)^(-) to Zn^(2+) + NH_(4)^(+) In basic medium, coefficients of Zn, NO_(3)^(-) and OH^(-) in the balanced equation are respectively.

Balance the following reactions by oxidation number method Zn+HNO_(3) rarr Zn ( NO_(3))_(2) + NO + H_(2) O

In the balanced equation of the reaction Zn+NO_(3)^(-)+OH^(-)toZnO_(2)^(2-)+NH_(3) , the coefficient of Zn,NO_(3)^(-)and OH^(-) respectively are-

For the reaction : Zn(s)+HNO_(3)(aq)toZn(NO_(3))_(2)(aq)+NH_(4)NO_(3)(aq)+H_(2)O(l) the change in oxidation number for per mole HNO_(2) is -

Statement -1: `Zn^(+2)` precipitated in the form of ZnS but not in the form `Zn(NO_(3))_(2)`. And
Statement -2: `S^(-2)` ion has high electron density w.r.t. `NO_(3)^(-)` ion.

`HNO_(3)` के साथ Zn की निम्नलिखित दो अभिक्रियाएँ दी गयी हैं- (समीकरण सन्तुलित नहीं है)
`Zn + सान्द्र HNO_(3) to Zn(NO_(3))_(2) + X + H_(2)O `…..(i)
`Zn + तनु HNO_(3) to Zn(NO_(3))_(2) + Y + H_(2)O`…..(ii)
(i) तथा (ii) अभिक्रिया में x तथा y यौगिक क्रमशः हैं-

Balance the following equations by oxidation number method.
`Zn + HNO_(3) to Zn(NO_(3))_(2) + H_(2)O + NH_(4)NO_(3)`

When Zn reacts with conc HNO_(3),then Zn(NO_(3))_2 and NO_(2) are formed , the reaction (s) involved in this process is/are

Zn + HNO_(3) = Zn (NO_(3))_(2) + N_(2) O + H_(2) O

Zn+2AgNO_(3) to Zn(NO_(3))_(2)+2Ag .