Assertion :When `H_(2)S` is passed through a solution of `CuSO_(4)` no precipitate of `CuS` is abtain until the solution is acidified with `HCI`
Reasion: The solution products constant of `CuS` is not so high as to require a high concen tration of `S^(2-)` for the precipitate of `CuS`

Options

A. If both (A) and (B) are correct and (R ) is the correct explqanation of (A)
B. If both (A) and (B) are correct but (R ) is not the correct explqanation of (A)
C. If (A) is correct ,but (R ) is incorrect
D. If (A) is incorrect ,but (R ) is correct

Answer

d

Explanation

It is true that precipitate of `CuS` does not requir a high concentration of `S^(2-)` ions But this does not mean that `CuS` will not precipitate with a higher concentration of `S^(2-)` In fact ,the precipitate will be faciliated by a high concentration of `S^(2-)` ,i.e. when the solution is not acidified so , (A) is false ,but (R ) is true