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Statement - I: A very dilute acidic solu...

Statement - I: A very dilute acidic solution of `Cd^(2+)` and `Ni^(2+)` gives yellow precipitate of CuS on passing `H_(2)S`
Statement - II : The solubility product of CdS is more than that of NiS

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The correct Answer is:
a
In qualitative analysis of basic radicalls cation `Cd^(2+)` belongs to group II `Ni^(2+)` Belongs to group IV group II radicals are precipitate by passsing `H_(2)S` in acidic solution .They have low value of solubility products .But that of group IV are precipitate by passing `H_(2)S` in alkline solution and have high value of solubility products
Therefore on passing `H_(2)S` in acidic solution a yellow precipirtate of CuS is formed
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Assertion : A very dilute acidic solution of `Cd^(2+)` and `Ni^(2+)` gives yellow ppt. of CdS on passing `H_(2)S`.
Statement: Solubility product of CdS is more than that of NiS.

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On passing H_(2)S gas through a highly acidic solution containing Cd^(2+) ions, CdS is not precipitated because

A very dilute acidic solution of `Cd^(2+)&Ni^(2+)` gives only yelllwo ppt. of CdS on passing `H_(2)S`, this is due to:

A very dilute acidic solution of `Cd^(2+) and Ni^(2+)` gives only yellow ppt. of CdS on passing `H_(2)S`, this is due to

वक्तव्य I `Cd^(2) तथा Ni^(2)` का एक बहुत तनु अम्लीय विलयन, `H_(2)S` गैस प्रवाहित करने पर CdS का हल्के पीले रंग का अवक्षेप देता है।
वक्तव्य || Cds का विलेयता गुणनफल, NIS के विलेयता गुणनफल से अधिक है।

Why only Cd^(2+) gets precipitated as CdS and not Ni^(2+) as Nis when H_2 S is passed through an acidic solution containing Cd^(2+) and Ni^(2+) ?

A very dilute acidic solution of Cd^(2+) and Ni^(2+) gives only yellow ppt. of CdS on passing H_(2)S , this is due to

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