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The work done when two mole of an ideal ...

The work done when two mole of an ideal gas is compressed form a volume of `5 m^(3)` to `1 dm^(3)` at 300 K , under a pressure of 100 kPa is

A

`499.9` kJ

B

`-499.9 `kJ

C

`-99.5` kJ

D

`42495`kJ

Text Solution

Verified by Experts

The correct Answer is:
A

Work done , W = `- P_(ext") (V_(2) - V_(1))`
Here , `P_("ext") = 100 k Pa`
`V_(1) = 5 m^(3) = 5 xx 10^(3) L implies V_(2) = 1 dm^(3) = 1 L`
`therefore W = -100 xx (1 - 500)`
` = - 499900 k PaL`
`= - 499900 J = - 499.9 kJ ( because 1 k Pa L = 1 J)`
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Knowledge Check

  • The work done when two moles of an ideal gas is compressed from a volume of 5m^(3) to 1dm^(3) at 300 K, under a pressure of 100 kPa is

    A
    `499.9 kJ`
    B
    `-499.9kJ`
    C
    `-99.5kJ`
    D
    `42495kJ`
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    A
    99 kJ
    B
    `-99` kJ
    C
    `114.9` kJ
    D
    `-114.9` kJ
  • What is the amount of work done when two moles of ideals gas is compressed from a volume of 1m^(3) to 10 dm^(3) at 300 k against a pressure of 100 kPa?

    A
    99 kJ
    B
    `-99 kJ`
    C
    114.9 kJ
    D
    `-114.9 kJ`
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