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A swimmer crosses the river along the li...

A swimmer crosses the river along the line making an angle of `45^@` with the direction of flow. Velocity of the river water is `5(m)/(s)`. Swimmer takes 12 seconds to cross the river of width 60 m. The velocity of the swimmer with respect to water will be:

A

`10(m)/(s)`

B

`5(m)/(s)`

C

`5sqrt5(m)/(s)`

D

`5sqrt2(m)/(s)`

Text Solution

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To solve the problem, we need to determine the velocity of the swimmer with respect to the water. Let's break down the solution step by step. ### Step 1: Understand the Problem The swimmer crosses a river that flows horizontally. The swimmer swims at an angle of 45 degrees to the flow of the river. The width of the river is 60 meters, and the velocity of the river is 5 m/s. The swimmer takes 12 seconds to cross the river. ### Step 2: Calculate the Velocity of the Swimmer in the Y-Direction The width of the river (the distance the swimmer needs to cross) is 60 meters, and the time taken to cross is 12 seconds. We can calculate the swimmer's velocity in the y-direction (the direction across the river) using the formula: \[ \text{Velocity in y-direction (Vy)} = \frac{\text{Distance}}{\text{Time}} = \frac{60 \, \text{m}}{12 \, \text{s}} = 5 \, \text{m/s} \] ### Step 3: Determine the Components of the Swimmer's Velocity Since the swimmer swims at a 45-degree angle to the flow of the river, the components of the swimmer's velocity with respect to the ground can be expressed as: \[ V_y = V_x \] Given that \( V_y = 5 \, \text{m/s} \), we can also conclude that: \[ V_x = 5 \, \text{m/s} \] ### Step 4: Write the Velocity of the Swimmer with Respect to the Ground The velocity of the swimmer with respect to the ground can be represented as a vector: \[ \vec{V}_{\text{swimmer (ground)}} = V_x \hat{i} + V_y \hat{j} = 5 \hat{i} + 5 \hat{j} \, \text{m/s} \] ### Step 5: Write the Velocity of the River The velocity of the river is given as: \[ \vec{V}_{\text{river}} = 5 \hat{i} \, \text{m/s} \] ### Step 6: Calculate the Velocity of the Swimmer with Respect to the Water To find the swimmer's velocity with respect to the water, we use the concept of relative velocity: \[ \vec{V}_{\text{swimmer (water)}} = \vec{V}_{\text{swimmer (ground)}} - \vec{V}_{\text{river}} \] Substituting the values we have: \[ \vec{V}_{\text{swimmer (water)}} = (5 \hat{i} + 5 \hat{j}) - (5 \hat{i}) = 5 \hat{j} \, \text{m/s} \] ### Step 7: Find the Magnitude of the Swimmer's Velocity with Respect to the Water The magnitude of the swimmer's velocity with respect to the water is simply: \[ |\vec{V}_{\text{swimmer (water)}}| = 5 \, \text{m/s} \] ### Final Answer The velocity of the swimmer with respect to the water is **5 m/s**. ---

To solve the problem, we need to determine the velocity of the swimmer with respect to the water. Let's break down the solution step by step. ### Step 1: Understand the Problem The swimmer crosses a river that flows horizontally. The swimmer swims at an angle of 45 degrees to the flow of the river. The width of the river is 60 meters, and the velocity of the river is 5 m/s. The swimmer takes 12 seconds to cross the river. ### Step 2: Calculate the Velocity of the Swimmer in the Y-Direction The width of the river (the distance the swimmer needs to cross) is 60 meters, and the time taken to cross is 12 seconds. We can calculate the swimmer's velocity in the y-direction (the direction across the river) using the formula: ...
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Knowledge Check

  • A swimmer crosses the river along the line making an angle of 45^(@) with the direction of flow. Velocity of the river is 5 m/s. Swimmer takes 6 seconds to cross the river of width 60 m. The velocity of the swimmer with respect to water will be :

    A
    `10m//s`
    B
    12m/s
    C
    `5sqrt(5)m//s`
    D
    `10sqrt(2)m//s`
  • Two swimmers A and B start swimming from different positions on the same bank as shown in figure.The swimmer A swims at angle 90^(@) with respect to the river to reach point P .He takes 120 seconds to cross the river of width 10m .The swimmer B also takes the same time to reach the point P

    A
    velocity of `A` with respect to river is `1//6 m//s`
    B
    river flow velocity is `1//4 m//s`
    C
    Velocity of `B` along `y`-axis with respect to earth is `1//3 m//s`.
    D
    Velocity of `B` along `x`-axis with respect to earth is `5//24 m//s`.
  • A swimmer crosses a river with minimum possible time 10 Second. And when he reaches the other end starts swimming in the direction towards the point from where he started swimming. Keeping the direction fixed the swimmer crosses the river in 15 sec. The ratio of speed of swimmer with respect to water and the speed of river flow is (Assume contant speed of river & swimmer)

    A
    `(3)/(2)`
    B
    `(9)/(4)`
    C
    `(2)/(sqrt5)`
    D
    `(sqrt5)/(2)`
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