Home
Class 12
MATHS
Find the equation of the circle which pa...

Find the equation of the circle which passes through the origin and intersects the circles below, orthogonally.
`x^2 + y^2 - 4x + 6y + 10 = 0 `.
`x^2 + y^2 + 12y + 6 = 0 . `

Text Solution

Verified by Experts

The correct Answer is:
`x^2 + y^2 - 7/2 x + y = 0`
`2x^2 + 2y^2 - 7x + 2y = 0.`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SYSTEM OF CIRCLE

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXERXCISE - 2(b)|23 Videos

  • SYSTEM OF CIRCLE

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXERXCISE - 2(b)|23 Videos

  • RANDOM VARIABLES AND PROBABILITY DISTRIBUTIONS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise EXERCISE - 7 (d)|4 Videos

  • THEORY OF EQUATIONS

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise DAM SURE LAQ -7 MARKS|4 Videos

Similar Questions

Explore conceptually related problems

Find the equation of the circle which passes through the origin and intersects the circles below, orthogonally. x^2 + y^2 - 4x - 6y - 3 = 0 . x^2 + y^2 - 8y + 12 = 0 .

Find the equation of the circle which passes through the origin and intersects each of the following circles orthogonally. x^2+y^2-4x+6y+10=0 x^2+y^2+12y+6=0

Knowledge Check

  • The equation of the circle which passes through the origin has its centre on the line x+y=4 and cuts orthogonally the circle x^2+y^2-4x+2y+4=0

    A
    `x^2+y^2-4x-4y=0`
    B
    `x^2+y^2-2x-6y=0`
    C
    `x^2+y^2-6x-2y=0`
    D
    `x^2+y^2+4x-12y=0`

    • Similar Questions

    Explore conceptually related problems

    Find the equation of the circle which passes through the origin and intersects each of the following circles orthogonally. x^2+y^2-4x-6y-3=0 x^2+y^2-8y+12=0

    Find the equation of the circle which passes through the origin and intersects each of the following circles orthogonally. x^(2)+y^(2)-4x+6y+10,x^(2)+y^(2)+12y+6=0

    Find the equation of the circle which passes through the point (0,-3) and intersects the circles given by the equation x^2 + y^2 - 6x + 3y + 5 = 0 and x^2 + y^2 - x - 7y = 0 orthogonally.

    Find the equation of the circle which passes through the point (2,0), (0,2) and orthogonally to the circle 2x^2 + 2y^2 + 5x - 6y + 4 = 0 .

    The equation of the circle passing through the origin and the point of intersection of the two circles x^(2) + y^(2) - 4x - 6y - 3 = 0 , x^(2) + y^(2) + 4x - 2y - 4 = 0 is

    The equation of the circle passing through the origin and the points of intersection of the two circles x^(2) + y^(2) - 4x - 6y - 3 = 0 , x^(2) + y^(2) + 4x - 2y = 0 " is " x^(2) + y^(2) - 28x - 18y = 0

    Find the equation of the circle which passes through the points (2,0)(0,2) and orthogonal to the circle 2x^2+2y^2+5x-6y+4=0 .

    Home
    Profile