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Two wooden blocks are moving on a smooth...

Two wooden blocks are moving on a smooth horizontal surface such that the mass `m` remains stationary with respect too block of mass `M` as shown in the figure. The magnitude of force `P` is:

A

`(M+m)g tanbeta`

B

`g tanbeta`

C

`mg cosbeta`

D

`(M+m)g cosesbeta`

Text Solution

Verified by Experts

The correct Answer is:
A
Acceleration of the system: `a(P)/(M+m) (1)`
The FBD of mass `m` is shown.
`Rsinbeta=ma` (2)
`Rcosbeta=mg` (3)
`A=gtanbeta`
Putting the value of a in (1), we get
`P=(M+m)gtanbeta` .
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Knowledge Check

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