What is the magnitude of the gravitational force between the Earth and a 1kg object on its surface ? (Mass of the earth is `6xx10^(24)` kg and radius of the Earth is `6.4xx10^(6) m)`.

Explanation

To find the magnitude of the gravitational force between the Earth and a 1 kg object on its surface, we can use Newton's law of universal gravitation, which is given by the formula:

\[ F = \frac{G \cdot M \cdot m}{r^2} \]

Where:
- \( F \) is the gravitational force,
- \( G \) is the gravitational constant \( (6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2) \),
- \( M \) is the mass of the Earth \( (6 \times 10^{24} \, \text{kg}) \),
...