Home
Class 9
PHYSICS
Calculate the force of gravitation betwe...

Calculate the force of gravitation between the earth the sun, given that the mass of the earth `=6xx10^(24)`kg and mass of the sun `=2xx10^(30)`kg. The average distance between the two is `1.5xx10^(11)m`.

Text Solution

Verified by Experts

Here, `F=?,m_(1)=6xx10^(24)kg, m_(2)=2xx10^(30)kg`
`r=1.5xx10^(11)m, G=6.7xx10-11Nm^(2)//kg^(2)`
`F=(Gm_(1)m_(2))/r^(2)=(6.7xx10^(-11)xx(6xx10^(24))xx(2xx10^(30)))/((1.5xx10^(11))^(2))=3.57xx10^(22)N`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Calculate the force of attraction between the earth and the sun, given that mass of earth is 6xx10^(24) kg abd mass of sun =2xx10^(30) kg. the average distance between the two is 1.5xx10^(11)m.

Find the distance of a point from the earth's centre where the resultant gravitational field due to the earth and the moon is zero. The mass of the earth is 6.0xx10^(24)kg and that of the moon is 7.4xx10^(22)kg . The distance between the earth and the moon is 4.0xx10^(5)km .

Knowledge Check

  • What is the binding energy of earth-sun system neglecting the effect of other planets and satellites? (Mass of earth M_(e ) = 6 xx 10^(24) kg , mass of the sun M_(s) = 2 xx 10^(30) kg^(-2) , distance between earth & sum = 1.5 xx 10^(11)m) Assuming circular orbit of earth around sun

    A
    `8.8 xx 10^(10)J`
    B
    `8.8 xx 10^3 J`
    C
    `5.2 xx 10^33 J`
    D
    `2.6 xx 10^33 J`

    • Similar Questions

    Explore conceptually related problems

    Find the distance of a point from the earth's centre where the resultant gravitational field due to the earth and the moon is zero The mass of the earth is 6.0 xx 10^(24)kg and that of the moon is 7.4 xx 10^(22)kg The distance between the earth and the moon is 4.0 xx 10^(5)km .

    Mass of mars is 6.42xx10^(29) kg and mass of the sun is 1.99xx10^(30)kg . What is the total mass?

    Find the distance of a point from the earth's centre where the resultant gravitational field due to the earth and the moon is zero. The mass of the earth is 6.0xx10^24 kg and that of the moon is 7.4x10^22 kg. The distance between the earth and the moon is 4.0xx10^5km .

    Calculat the binding energy of the - sum system . Mass of the earth =6xx 10 ^(24) kg , mass of the sun = 2 xx 10^(30) kg, distance between the earth and the sun = 1.5 xx 10^(11) and gravitational constant = 6.6 xx 10 ^(-11) N m^(2) kg^(2)

    Find the magnitude of the gravitational force between the Sun and the earth. (Mass of the Sun =2xx10^(30) kg, mass of the earth =6xx10^(24)kg and the distance between the centres of the Sun and the earth =1.5xx10^(11)m , (G=6.67xx10^(-11)N.m^(2)//kg^(2))

    The earth revolves round the sun due to gravitatinal attraction. Suppose that the sun and the earth are point particle with their existing masses and that Bhor's quantization rule for angular monentum is valid in the case of gravitation (a) Calculate the minimum radius the earth can have for its orbit. (b) What is the value of the principle quantum number n for the present radius ? Mass of the earth = 6.0 xx 10^(24) kg, mass of the sun = 2.0 xx 10^(30) kg, earth-sun distance = 1.5 xx 10^(11)m .

    Find the gravitational force between the sun and the Jupiter. Given that the mass of the sun = 2 xx 10^(30) kg, the mass of the Jupiter = 1.89 xx 10^(27) kg, the radius of the Jupiter's orbit = 7.73 xx 10^(11) m and the value of universal gravitational constant G = 6.67 xx 10^(11) N m^(2) kg^ (2) .

    Home
    Profile