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The displacement (in metre) of a particl...

The displacement (in metre) of a particle moving along x-axis is given by `x=18t +5t^(2).` Calculate (i) the instantaneous velocity `t=2 s` (ii) average velocity between `t=2 s` to `t=3 s` (iii) instantaneous acceleration.

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Let's solve the given problem step by step. ### Given: The displacement \( x \) of a particle moving along the x-axis is given by: \[ x = 18t + 5t^2 \] ### (i) Instantaneous Velocity at \( t = 2 \) seconds ...
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The displacement (in metre) of a particle moving along x-axis is given by x=18t+5t^2.Calculate (i) the instantaneous velocity at t=2s.

The displacement of a particle moving along an x axis is given by x=18t+5.0t^(2) , where x is in meters and t is in seconds. Calculate (a) the instantaneous velocity at t=2.0s and (b) the average velocity between t=2.0s and t=3.0s .

Knowledge Check

  • The displacement (in metre) of a particle moving along X-axis is given by x=18t+5t^(2) . The average acceleration during the interval t_(1)=2s and t_(2)=4s is

    A
    `13 ms^(-2)`
    B
    `10 ms^(-2)`
    C
    `27 ms^(-2)`
    D
    `37 ms^(-2)`
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