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Calculate the power of an engine , which...

Calculate the power of an engine , which can just pull a train of mass 5000 quintals up an incline of 1 in 50 at the rate of `54 km//h` . The resistance due to friction is` 0.8 N //"quintal"`. Take `g = 9.8 m//s^(2)` .

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Here , power , ` P' = ? M = 5000 "quintals" = 5 xx 10^(5) kg `
`sin theta = (1)/(50) , v = 54 km//h = (54 xx 1000)/(60 xx 60) = ms^(-1) = 15 ms^(-1) `
Force of friction , `F = 0.8 N// "quintal" = 0.8 xx 5000 N = 4000 N`
`P' = (W)/(t) = (mg sin theta + F )xx (S)/(t) = (mg sin theta + F ) xx v`
`P' = (5 xx 10^(5) xx 9.8 xx (1)/(50) + 4000 )15 `
`P' = (98000 + 4000) xx 5 = 1530000 W = 1530 km ` .
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