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A mass of 4 kg rest on a horizontal plan...

A mass of 4 kg rest on a horizontal plane . The plane is gradually inclined until an angle `0 = 15^(@)` with the horizontal and the mass just begins to slide . What is the coefficient of static friction between the block and the surface ?

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Here, `m = 4 kg , theta = 15^(@) , mu_(s) = ?`
As the mass just begins to slide at this angle of inclination , therefore , `theta = 15^(@) = alpha`,
The angle of repose . ` mu_(s) = tan alpha = tan 15^(@) = 0 . 27 `
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