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In the following P-V diagram two adiabat...

In the following P-V diagram two adiabatics cut two isothermals at temperature `T_(1) and T_(2)` (fig). The value of `V_(a)/V_(d)` will be

A

`V_(b)/V_(c)`

B

`V_(c)/V_(b)`

C

`V_(d)/V_(a)`

D

`V_(b)V_(c)`

Text Solution

Verified by Experts

The correct Answer is:
A
For adiabatic process `T_(1) V_(b)^(gamma-1)` = constant
For `bc` curve `T_(1)V_(b)^(gamma-1) = T_(2)V_(C)^(gamma-1)` or `(T_2)/(T_1) = ((V_b)/(V_c))^(gamma-1)`
For `ad` curve `T_(1)V_(a)^(gamma-1) = T_(2) V_(c)^(gamma-1)` or `(T_2)/(T_1) = ((V_a)/(V_d))^(gamma-1)`
From equation (i) and (ii) , `(V_b)/(V_c) = (V_a)/(V_d)`.
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Knowledge Check

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