Give the structure of an optically active alkene `(A)` having the lowest molecular mass, which on catalytic hydrogenation gives an optically inactive compound `(B)`.

Explanation

For a compound to be an optically active alkene, with the lowest molecular mass, there should be four different groups around the `C` atom. One of the groups should be `(H)`, another should be alkene group `(-CH=CH_(2))`, and the remaining two groups should be `(Me)` and `(Et)`. So the compound `(A)` is `:`