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For x"inR,f(x)=|log2-sinx|andg(x)=f(f(x)...

For `x"inR,f(x)=|log2-sinx|andg(x)=f(f(x)),` then

A

g is not differentiable at `x=0`

B

`g'(0)=cos(log2)`

C

`g'(0)=-cos(log2)`

D

`g` is differentiable at `x=0andg'(0)=-sin(log2)`

Text Solution

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The correct Answer is:
b
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Knowledge Check

  • For x in R,f(x)=|log2-sinx| and g(x)=f(f(x)) , then

    A
    g is not differentiable at x = 0
    B
    `g'(0)=cos(log 2)`
    C
    `g'(0)=-cos(lgo2)`
    D
    g is differentiable at x = 0 and `g'(0)=-sin(log2)`
  • If f(x)=sinx+|sinx|andg(x)=f(x-pi)+f(x+2pi) , then value of underset(-2pi)overset(5pi)(f)g(x)dx is

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    15
    B
    7
    C
    12
    D
    28
  • If f(x)=log(1+x)andg(x)=e^(x) , then the value of (gof) (x) is :

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    `e^(1+x)`
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    `1+x`
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