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How many moles of NaOH are contained in ...

How many moles of `NaOH` are contained in `27 mL` of `0.15 M NaOH`?

Text Solution

Verified by Experts

Milli-moles of `NaOH=MxxV_("in"mL)=0.15xx27`
`:.` Moles of `NaOH=(0.15xx27)/(1000)= 4.05xx10^(-3)`
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Knowledge Check

  • How many grams of NaOH are present in 250 mL of 0.5 M NaOH solution?

    A
    7.32 g
    B
    3.8 g
    C
    5g
    D
    0.5 g
  • 4.0 g of NaOH contains

    A
    `6.022 xx 10^(23)` atoms of H
    B
    4 g atoms of Na
    C
    `6.022 xx 10^(22)` atoms of Na
    D
    4 moles of NaOH
  • How many grams of NaOH will be needed to prepare 250 mL of 0.1 M solution-

    A
    1 g
    B
    10 g
    C
    4 g
    D
    6 g
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