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The mole fraction of the solute in one m...

The mole fraction of the solute in one molal aqueous solution is:

A

`0.009`

B

`0.0018`

C

`0.027`

D

`0.036`

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The correct Answer is:
To find the mole fraction of the solute in a one molal aqueous solution, we can follow these steps: ### Step 1: Understand the Definition of Molality Molality (m) is defined as the number of moles of solute per kilogram of solvent. In this case, we have a one molal solution, which means there is 1 mole of solute in 1 kg of solvent (water). ### Step 2: Calculate Moles of Solvent To find the mole fraction, we need to calculate the number of moles of the solvent (water). The molecular weight of water (H₂O) is approximately 18 g/mol. Since we have 1 kg (or 1000 g) of water: \[ \text{Moles of water} = \frac{\text{mass of water}}{\text{molecular weight of water}} = \frac{1000 \, \text{g}}{18 \, \text{g/mol}} \approx 55.56 \, \text{moles} \] ### Step 3: Calculate Total Moles Now we can find the total number of moles in the solution. We have 1 mole of solute and approximately 55.56 moles of solvent. Therefore, the total moles in the solution is: \[ \text{Total moles} = \text{moles of solute} + \text{moles of solvent} = 1 + 55.56 = 56.56 \, \text{moles} \] ### Step 4: Calculate Mole Fraction of Solute The mole fraction of the solute (X_solute) is given by the formula: \[ X_{\text{solute}} = \frac{\text{moles of solute}}{\text{total moles}} = \frac{1}{56.56} \approx 0.0177 \] ### Step 5: Final Answer Thus, the mole fraction of the solute in a one molal aqueous solution is approximately 0.0177. ### Summary of Steps: 1. Define molality and identify the number of moles of solute. 2. Calculate the moles of solvent using its mass and molecular weight. 3. Find the total moles in the solution. 4. Use the formula for mole fraction to calculate the mole fraction of the solute.

To find the mole fraction of the solute in a one molal aqueous solution, we can follow these steps: ### Step 1: Understand the Definition of Molality Molality (m) is defined as the number of moles of solute per kilogram of solvent. In this case, we have a one molal solution, which means there is 1 mole of solute in 1 kg of solvent (water). ### Step 2: Calculate Moles of Solvent To find the mole fraction, we need to calculate the number of moles of the solvent (water). The molecular weight of water (H₂O) is approximately 18 g/mol. Since we have 1 kg (or 1000 g) of water: ...
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P BAHADUR-MOLE AND EQUIVALENT CONCEPT-Exercise (3A) Objective problems:
  1. A solution is 0.5M in MgSO(4), 0.1MACl(3) and 0.2 M in (NH(4))(2)SO(4...

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  2. Equal masses of O(2), H(2) and CH(4) are taken in a container. The res...

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  3. The mole fraction of the solute in one molal aqueous solution is:

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  4. In the solubility of liquid solutions:

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  5. After equal volume of 0.10 M solutions of (NH(4))(2)SO(4) and Ba(OH)(2...

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  6. Chlorophyll, a green colouring matter contains 2.68% Mg. The number of...

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  7. 16g of SO(x) occupies 5.6 litre at STP. Assuming ideal gas nature, the...

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  8. The radius of a water molecule having density 1.0g mL^(-1) is :

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  9. Number of positive ions in 1.45 mole of K(2)SO(4) are:

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  10. Equal moles of H(2)O and NaCl are present in a solution. The molality ...

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  11. The weight of 1 xx 10^(22) molecules of CuSO(4). 5H(2)O is

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  12. Weight of one atom an element is 6.44 xx 10^(-23) g. Calculate g atom ...

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  13. A compound contains 10^(-2)% of phosphorus. If atomic mass of phosphor...

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  14. Total number of electrons present in 11.2 litre of NH(3) at STP are:

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  15. Al(2)(SO(4))(3).XH(2)O has 8.1% aluminium by mass. The value of X is:

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  16. One litre of N(2) and 7//8 litre of O(2) under identical conditions of...

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  17. Total number of atoms present in 1.0 cm^(3) of solid urea (density 0.3...

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  18. The density of liquid (mol.wt. = 70) is 1.2 g mL^(-1). If 2 mL of liqu...

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  19. The atomic weight of a triatomic gas is a. The correct formula for the...

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  20. A solution required [OH^(-)]=2M. If degree of dissociation of Mg(OH)(2...

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