The equivalent weight of iron in `Fe_(2)O` would be:

Options

A. `18.6`
B. `26.66`
C. `56`
D. `112`

Explanation

To find the equivalent weight of iron in FeO2, we can follow these steps:

### Step 1: Determine the atomic weight of iron (Fe)
The atomic weight of iron (Fe) is approximately 56 g/mol.

### Step 2: Determine the valency of iron in FeO2
In the compound FeO2, iron is in the +4 oxidation state (Fe^4+) because oxygen typically has a -2 oxidation state. Since there are two oxygen atoms, the total negative charge is -4, which means iron must have a +4 charge to balance it. Therefore, the valency of iron in FeO2 is 4.

### Step 3: Calculate the equivalent weight of iron
The formula for equivalent weight is given by:
\[ \text{Equivalent Weight} = \frac{\text{Atomic Weight}}{\text{Valency}} \]

Substituting the values we have:
\[ \text{Equivalent Weight of Fe} = \frac{56}{4} \]

### Step 4: Perform the calculation
\[ \text{Equivalent Weight of Fe} = 14 \]

### Final Answer
The equivalent weight of iron in FeO2 is 14 g/equiv.

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