Assuming 100% ionisation, the solution h...

Assuming `100%` ionisation, the solution having highest normality is:

`1 M H_(2)SO_(4)`

`1 M H_(3)PO_(3)`

`1 M H_(3)PO_(4)`

`1 M HNO_(3)`

Text Solution

Verified by Experts

The correct Answer is:

`H_(3)PO_(4)` is tribasic, thus
`1 MH_(3)PO_(4)-=3NH_(3)PO_(4) at 100% "ionisation"`

Topper's Solved these Questions

MOLE AND EQUIVALENT CONCEPT
P BAHADUR|Exercise Exercise(3B)Objective problems|15 Videos
MOLE AND EQUIVALENT CONCEPT
P BAHADUR|Exercise Exercise (4) Objective problems|20 Videos
MOLE AND EQUIVALENT CONCEPT
P BAHADUR|Exercise Exercise (2) prevous year numberical problems|25 Videos
IONIC EQUILIBRIUM
P BAHADUR|Exercise Exercise|85 Videos
RADIO ACTIVITY
P BAHADUR|Exercise Exercies 9|99 Videos

Similar Questions

Explore conceptually related problems

Assuming complete ionisation, the solution having maximum freezing point will be:

A complex is written as M(en)_(y)Br . Its 0.05 molar solution shows 2.46 atm osmotic pressure at 27^(@)C . Assuming 100% ionisation and coordination number of metal (III) is six, complex may be

1 mol each of the following solutes are taken in 5 mol water, (a) NaCl (b) K_(2)SO_(4) ( C) Na(3)PO_(4) (d) glucose Assuming 100% ionisation of the electrolyte ,relative decrease in vapour pressure will be in order

An aqueous solution of a solute AB has b.p. of 101.08^(@)C( AB is 100% ionised at boiling point of the solution ) and freezes at -1.80 ^(@)C . Hence, AB(K_(b)//K_(f)=0.3)

An aqueous solution of a solute AB has b.p of 101.08^(@)C (AB is 100% ionised at boiling point of the solution ) and freezes at -1.80^(@)C . Hence , AB ( K_(b) //K_(f) = 0.3) :

Assuming 100% ionization in case of strong electrolytes which of the following will have minimum pH

The element having highest ionisation potential is

P BAHADUR-MOLE AND EQUIVALENT CONCEPT-Exercise (3A) Objective problems:

100 mL of mixture of NaOH and Na(2)SO(4) is neutralised by 10 mL of 0....
Text Solution
|
0.05 moles of NaHCO(3) will react with how many equivalent of Mg(OH)(2...
Text Solution
|
0.078 g Al(OH)(3). is dehydrated to Al(2)O(3). The Al(2)O(3) so obtain...
Text Solution
|
Assuming 100% ionisation, the solution having highest normality is:
Text Solution
|
100 mL of a sample of hard water requires 25.1 mL of 0.02 N H(2)SO(4) ...
Text Solution
|
The equivalent weight of potash alum (K(2)SO(4).Al(2)(SO(4))(3).24H(...
Text Solution
|
Vapour density of a metal chloride is 6.6. Its oxide contains 53% meta...
Text Solution
|
100 mL of 0.1 M solution of H(2)SO(4) is used to prepare 0.05N solutio...
Text Solution
|
Which does not change on dilution?
Text Solution
|
20 mL of 0.1M H(3)BO(3) solution on complete netralisation requires …....
Text Solution
|
Volume strength of H(2)O(2) labelled is 10 vol. What is normality of H...
Text Solution
|
Find the weight of H(2) SO(4) in 1200 mL of a solution of 0.2 N streng...
Text Solution
|
Calculate the volume of 0.5 M H2SO4 required to dissolve 0.5 g of copp...
Text Solution
|
1 g of calcium was burnt in excess of O(2) and the oxide was dissolved...
Text Solution
|
Number of H^(+) ions in 100 mL of 0.001 M H(2)SO(4) is:
Text Solution
|
3 g of an oxide of a metal is converted completely to 5 g chloride. Eq...
Text Solution
|
V(1) mL of NaOH of normality X and V(2) mL of Ba(OH)(2) of mormality Y...
Text Solution
|
Weight of oxygen in Fe(2)O(3) and FeO in the simple ratio for the same...
Text Solution
|
An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 m...
Text Solution
|
0.63 g of diabasic acid was dissolved in water. The volume of the solu...
Text Solution
|