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What would be the molality of a solution...

What would be the molality of a solution obtained by mixing equal volumes of `30%` by weight `H_(2)SO_(4) ( d= 1.218 g mL^(-1))` and `70%` by weight `H_(2)SO_(4) ( d= 1.610g mL^(-1))` ? If the resulting solution has density `1.425g//mL`, calculate its molarity.

Text Solution

Verified by Experts

The correct Answer is:
`7.61, 11.22`;
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What is would be the molality of a solution obtained by mixing equal volumes of 30% by weight H_(2) SO_(4) (d = 1.218 g mL^(-1)) and 70% by weight H_(2) SO_(4) (d = 1.610 g mL^(-1)) ? If the resulting solution has density 1.425 g mL^(-1) , calculate its molality.

Calculate the molality and molarity of a solution made by mixing equal volumes of 30% by weight of H_(2)SO_(4) (density =1.218g//mL ) and 70% by weight of H_(2)SO_(4) (density =1.610g//mL )

Knowledge Check

  • Calculation the molarity and molality of a solution made by mixing equal volumes of 35% by mass of H_(2)SO_(4) (density= 1.22 g mL^(-1)) and 65% by H_(2)SO_(4) (density =1.62 g mL^(-1)) .

    A
    `8.66 M, 13.3 m`
    B
    `5.77 M, 10.1 m`
    C
    `9.86 M, 12.2 m`
    D
    `7.55 M, 11.1 m`

  • The molarity of 98% by wt. H_(2)SO_(4) (d = 1.8 g/ml) is

    A
    6 M
    B
    18 M
    C
    10 M
    D
    4 M

  • Calculate the pH of solution obtained by mixing 10 ml of 0.1 M HCl and 40 ml of 0.2 M H_(2)SO_(4)

    A
    `0.3685`
    B
    `0.4685`
    C
    `1.3685`
    D
    `1.4684`

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    Equal volumes of 30% by mass of H_(2)SO_(4) (density 1.218g mL^(-1)) and of H_(2)SO_(4) (density 1.610 g mL^(-1)) are mixe. If the density of te mixture is 1.452 g mL^(-1) , calculate the molarity oand molality of the solution.

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