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The specific heats of a gas are 0.125 an...

The specific heats of a gas are 0.125 and `0.075` cal/g Calculate the atomicity and molecular weight of gas Identify the gas .

Text Solution

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`C_(P) = 0.125 cal//g`
`C_(V) = 0.075 cal//g`
`:' C_(P) -C_(v) = (R )/(M)`
`:. 0.125 -0.075 = (2)/(M)`
`:. M =40`
Also `(C_(p))/(C_(v)) =gamma = (0.125)/(0.075) =1.66`
Thus gas is monoatomic with mol wt `=40 `and so Argon .
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Knowledge Check

  • The specific heat of gas

    A
    has only two values `Cp` & `Cv`
    B
    has a unique value of given temperature
    C
    can have any values from `O` to `prop`
    D
    depends upon the mass of the gas

  • The specific heat of a gas can have

    A
    only two values at constant pressure and constant volume
    B
    only one value at a given temperature
    C
    any value between zero and infinity
    D
    None of the above is correct

  • The specific heat of a gas in an isothermal process is

    A
    infinite
    B
    Zero
    C
    Negative
    D
    Remains constant

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