The average oxidation number of `I` in `KI_(3), Fe` in `Fe_(3)O_(4)` are respectively:

Options

A. `-1//3, +8//3`
B. `-1, +8`
C. `0,+3`
D. `0,+2`

Answer

A

Explanation

Average oxidation no. of `I` in `Kl_(3)`
or `overset(-1)(KI)+overset(0)I_(2)=((-1xx1)+2xx0)/(3)=(-1)/(3)`
Average oxidation no. of `Fe` in `Fe_(3)O_(4)`
or `Fe_(2)overset(+)O_(3).Feoverset(+2)O=((+3xx2)+(+1xx1))/(3)=(+8)/(3)`
Average ox.no. `=(SigmaOx."No".xx"No.of atoms")/("No.of atoms")`