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The incident ray and the refracted ray o...

The incident ray and the refracted ray of light are on the opposite sides of the normal at the point of incidence.

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A ray of light is incident on a plane mirror, making an angle 'q' with the surface of the mirror. Arrange the following steps in sequential order to calculate the angle between the incident light ray and the reflected light ray. (A) Draw a normal line on the plane mirror at the point of incidence of the light ray. (B) Note down the angle between the plane mirror and the incident light ray. (C) The sum of the angle of incidence and the angle between the plane mirror and the incident ray is 90^(@) .Determine the angle of incidence. (D) From the laws of reflection, the angle of incidence is equal to the angle of reflection. Then the sum of the angle of incidence and the angle of reflection gives the angle between the incident light ray and the reflected light ray.

A light ray passes from air to denser medium of certain thickness and emerges on the other side. If emergent ray is parallel to the incident ray, the distance travelly by the ray of light in the denser medium is 6 cm, and the angle of incidence and refraction are 60^(@) and 30^(@) , respectively, find the lateral displacement of the light ray.

A ray of light is incident on a plane mirror at an angle of 20^(@) with the normal, at the point of incidence, Through what angle, the ray of light will be deviated from its direction of incidence ?

Choose the correct statement regarding the incident ray, refracted ray and normal drawn at the point of incidence.

Read the following statements and choose the correct option. (A) The angle made by the incident light ray with the plane of mirror is equal to the angle made by the reflected light ray with the plane of mirror. (B) The angle between an incident light ray and a reflected light ray is twice that of the angle between the incident light ray and normal.