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Power of a lens , P=(1)/(f)...

Power of a lens , `P=(1)/(f)`

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To solve the question regarding the power of a lens, we need to understand the relationship between the power (P) and the focal length (f) of the lens. The formula given is: \[ P = \frac{1}{f} \] where: - \( P \) is the power of the lens, - \( f \) is the focal length of the lens. ### Step-by-Step Solution: 1. **Understanding the Formula**: - The formula states that the power of a lens is the reciprocal of its focal length. 2. **Units of Focal Length**: - The focal length \( f \) must be measured in meters (m) for the formula to be valid. 3. **Calculating Power**: - To find the power \( P \), you take the reciprocal of the focal length. If \( f \) is given in meters, then: \[ P = \frac{1}{f} \text{ (in meters)} \] 4. **Units of Power**: - The unit of power is the diopter (D). Therefore, when you calculate \( P \), the result will be in diopters. 5. **Sign Convention**: - It is important to note the sign convention: - For converging lenses, the focal length is positive. - For diverging lenses, the focal length is negative. 6. **Final Statement**: - The statement that the power of a lens is given by \( P = \frac{1}{f} \) is correct, provided that the focal length is in meters and the appropriate sign is used. ### Summary: - The power of a lens is calculated using the formula \( P = \frac{1}{f} \). - Ensure \( f \) is in meters. - The unit of power is diopter (D). - Use the correct sign for the focal length based on the type of lens.
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The power of lens is P=1/(f') where f is focal length of the lens. The dimensions of power of lens is

Power of a lens is a measure of the ability of the lens to converge the rays of light falling on it. Quantitatively, power of a lens = reciprocal of focal length of lens, i.e., P=(1)/(f) . If a lens happens to diverge the ray of light falling on it, its power is said to be negative. Thus, power of a convex lens is positive and power of a concave lens is negative. If P_1,P_2 are powers of two lenses held in contact with each other, the power of the combination is P=P_1+P_2 . Note that P_1,P_2 are to be added with proper sign. Read the above passage and answer the following question: (i) What is the SI unit of power? (ii) Focal length of a concave lens is 20 cm . What is its power ? (iii) What lessons of life do you learn from the relation P=P_1+P_2 ?

Knowledge Check

  • If two power of a thick lense is P_(1) and that of a thin lens is P_(2) then

    A
    `P_(1) lt P_(2)`
    B
    `P_(1)= P_(2)`
    C
    `P_(1) gt P_(2)`
    D
    `P_(1)= (P_(2))/(2)`
  • Power of a lens of focal length 1 cm is

    A
    1D
    B
    10D
    C
    100 D
    D
    `(1)/(100)D`
  • The power (P) of a lens of focal length (f) is given by

    A
    P = f
    B
    `P = (1)/(f)`
    C
    `P = -(1)/(f)`
    D
    `P = -f`
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    Power Of Lens

    What is the power of a lens ?

    What is the power of a lens ?

    Power (P) of a lens is given by reciprocal of focal length (f) of the lens. i.e. P = 1//f . When f is in metre, P is in dioptre. For a convex lens, power is positive and for a concave lens, power is negative. When a number of thin lenses of powers p_(1), p_(2), p_(3).... are held in contact with one another, the power of the combination is given by algebraic sum of the powers of all the lenses i.e., P = p_(1) + p_(2) + p_(3) + ........ Answer the following questions : When a third lens of focal length - 20 cm is placed in contact with the two lenses, power of the three would be

    Power (P) of a lens is given by reciprocal of focal length (f) of the lens. i.e. P = 1//f . When f is in metre, P is in dioptre. For a convex lens, power is positive and for a concave lens, power is negative. When a number of thin lenses of powers p_(1), p_(2), p_(3).... are held in contact with one another, the power of the combination is given by algebraic sum of the powers of all the lenses i.e., P = p_(1) + p_(2) + p_(3) + ........ Answer the following questions : Power of second lens is